| VB6 Split Function
k, so I have this right here.
"digna_kratowicz" : "dhdhd" : "digna_kratowicz@mailin8r.com"
On one line, on a list. I call this line of the list to a string "strUsr".
I want only the first part, "digna_kratowicz" (without the quotations). Then, in a separate string, the password "dhdhd" (again without the quotations). I want the last email part to gtfo (its not important.).
How would I make use of this split function to get it. I've looked around but most of the things I try don't seem to work.
+rep to helperz?
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Hatz =D  | 
